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Kamis, 21 Februari 2008

STRATEGI DELIVERY moon Chem

Delivery Strategy at MoonChem

John Kresge adalah Vice President Supply chain MoonChem, sebuah perusahaan manufaktur yang memproduksi bahan kimia khusus. Setelah meeting di MoonChem, dalam evaluasi kinerja financial diketahui bahwa perusahaan itu hanya meraih dua perputaran inventory setahun, lebih dari setengah inventory yang dimiliki ada dalam pengiriman (titipan) ke konsumennnya. Hal ini mengejutkan karena hanya 20% dari konsumen tersebut yang membawa inventory titipan. John bertanggungjawab atas inventory, sama halnya dengan biaya transportasi.Dia memutuskan untuk mencermati manajemen inventory titipan dan menyusun rencana yang tepat.
MoonChem Operations
MoonChem mempunyai delapan pabrik dan 40 distribution centers. Pabrik tersebut memproduksi bahan kimia dasar dan distribution center mencampurnya untuk membuat ratusan produk akhir yang memenuhi spesifikasi konsumen. Pada pasar bahan kimia khusus, MoonChem berusaha untuk mendiferensiasikan dirinya di wilayah Midwest dengan menyediakan inventori titipan kepada pelanggannya.

Perusahaan ingin menggunakan strategi ini secara nasional jika terbukti efektif. MoonChem membiarkan bahan kimia diperoleh tiap pelanggan di wilayah Midwest sebagai penitipan atau konsinyasi di tempat pelanggan. Pelanggan menggunakan bahan kimia sesuai yang merka butuhkan, dan MoonChem mengatur perlengkapan untuk memastikan ketersediaan. Pada situasi kebanyakan, konsumsi bahan kimia oleh konsumen sangat stabil. MoonChem memiliki penitipan inventory dan dibayar atas penggunaan bahan kimia yang telah mereka gunakan.

Distribution at MoonChem
MoonChem menggunakan Golden Trucking, truk pengangkut muatan penuh untuk semua pengiriman. Tiap truk mempunyai kapasitas 40.000 pounds, dan Golden memberikan tariff tetap atas asal dan tujuan, tidak melihat kuatntitas yang dikirimkan denga truk tersebut. MoonChem mengirimkan truk muatan penuh kepada tiap konsumen untuk melengkapi inventory titipan mereka.

The Illinois Pilot Study
John memutuskan untuk mencermati operasi distribusi. Dia focus kepada Negara bagian Illinois, yand disupplai dari Chicago distribution center. Dia memecah Illinois ke dalam kumpulan kode pos yang berdekatan seperti pada gambar. Dia membatasi perhatian pada wilayah Peoria, yang diklasifikasikan sebagai kode pos 615. Pada studi yang seksama pada wilayah ini ditemukan dua pelanggan besar, enam pelanggan medium, dan 12 pelanggan kecil. Konsumsi pertahun pada tiap tipe pelanggan seperti pada tabel. Golden memasang tarif $400 untuk tiap pengiriman dari Chicago ke Peoria, dan kebijakan MoonChem adalah mengirim truk muatan penuh untuk tiap pelanggan sesuai kebutuhan.

Customer Profile funtuk MoonChem di wilayah Peoria
Customer Type Number of Customer Consumtion
(Pounds per month)
Small 12 1000
Medium 6 5.000
Large 2 12.000
John mengecek dengan Golden untuk mencari tahu apa yang harus dilakukan untuk memasukkan pengiriman kepada beberapa pelanggan dalam satu muatan. Golden menginformasikan padanya bahwa mereka akan melanjutkan untuk memberikan tarif $350 per truk dan kemudian menambahkan $50 untuk tiap drop-off yang harus ditanggung oleh Golden. Oleh karena itu, jika Golden membawa truk yang harus dibuat untuk sekali pengiriman, total tarif sebesar $400. Bagaimanapun jika truk harus melakukan empat kali pengiriman , total tarif sebesar $550.

Tiap pound dari bahan kimia pada biaya penitipan MoonChem $1, dan holding cost 25%. John ingin menganalisa pilihan yang berbeda tiap distribusi yang tersedia di wilayah Peoria untuk menentukan kebijakan distribusi yang optimal. Studi lebih detail dari wilaya Peoria akan menyediakan blueprint untuk strategi distribusi yang direncanakan MoonChem untuk diterapkan secara nasional.

Analisis Pertanyaan
  1. Annual Cost
Jenis biaya tahunan yang harus dikeluarkan oleh MoonChem adalah
    • Annual Holding Cost
    • Annual Shipment Cost
Komponen:
    • Biaya pengiriman (shipment cost): $350 per truk
    • Tambahan biaya pengiriman: $50 per drop-off
    • Holding cost:25%
    • Unit cost: $1 per pounds

  1. Different delivery options
If each type of customers are delivered independently
      • Number of customers
        1. Small = 12 Consumption per year = 1000 x 12 = 12.000 pounds
        2. Medium = 6 Consumption per year = 5000 x 12 = 60.000 pounds
        3. Large = 2 Consumption per year = 12.000 x 12 = 144.000 pounds
      • Holding cost, h = 0,25
      • Unit cost per pound, C = $1
      • Common transportation cost, S = $ 350 per truck
      • Transportation specific cost, si = $ 50 per drop off
    • Small Customers
      • Combined shipment cost for 12 customers:
S* = S + s1 + ...+ s12
S* = $ 350 + (12 x $ 50 ) = $ 950
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(12 x 12.000 x 0,25 x $1) / 2 x $950
2 S*
= √36.000 / 1.900
= 4,3 ≈ 5 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 5 x ($950/12) = $395,8
      • Quantity Shipped for Each Customers:
Q = 12.000 / 5 = 2.400 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (2.400/2)
= $300
      • Total Capacity per truck:
Total capacity per truck = 12 x 2400 = 28.800
      • No added frequency
    • Medium Customers
      • Combined shipment cost for 6 customers:
S* = S + s1 + ...+ s6
S* = $ 350 + (6 x $ 50 ) = $ 650
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(6 x 60.000 x 0,25 x $1) / 2 x $650
2 S*
= √90.000 / 1.300
= 8,32 ≈ 9 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 9 x ($650/6) = $975
      • Quantity Shipped for Each Customers:
Q = 60.000 / 9 = 6.666 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (6.666/2)
= $833,3
      • Total Capacity per truck:
Total capacity per truck = 6 x 6.666 = 39.996
No added frequency
    • Large Customers
      • Combined shipment cost for 2 customers:
S* = S + s1 + s2
S* = $ 350 + (2 x $ 50 ) = $ 450
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(2 x 144.000 x 0,25 x $1) / 2 x $450
2 S*
= √72.000 / 900
= 8,94 ≈ 9 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 9 x ($450/2) = $2.025
      • Quantity Shipped for Each Customers:
Q = 144.000 / 9 = 16.000 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (16.000/2)
= $4000
      • Total Capacity per truck:
Total capacity per truck = 2 x 16.000 = 32.000
No added frequency
Total Cost:
Small = ($395,8 x 12 ) + ($300 x 12) = $ 8.349,6
Medium = ($975x 6 ) + ($833,3 x 6) = $10.849,8
Large = ($2.025 x 2 ) + ($4000 x 2) = $12.050,0
Total $31.249.4
If small customers are delivered independently and medium & large customers are delivered jointly
    • Medium & Large Customers
      • Combined shipment cost for 2 customers:
S* = S + s1 +...+ s8
S* = $ 350 + (8 x $ 50 ) = $ 750
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(8 x 204.000 x 0,25 x $1) / 2 x $750
2 S*
= √408.000 / 1.500
= 16.5 ≈ 17 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 17 x ($750/8) = $1.593,75
      • Quantity Shipped for Each Customers:
Q = 204.000 / 17 = 12.000 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (12.000/2)
= $1.500
      • Total Capacity per truck:
Total capacity per truck = 8 x 12.000 = 96.000
Need added frequency
Shipment quantity for each truckload = 40.000/8 = 5.000
Increased in shipment frequency = 204.000/5000 = 40.8 ≈ 41 x
Increased in annual shipment per customers = 41 x ($750/8) = $3.843,75
Decreased in annual holding cost
Q = 204.000/41 = 4.976
Annual holding cost = 0,25 x 1 x (4.976/2) = $622
Total Cost:
Small = ($395,8 x 12 ) + ($300 x 12) = $ 8.349,6
Medium & Large = ($3.843,75x 8 ) + ($622 x 8) = $ 35.726,0
Total $44.075,6
If medium customer are delivered independently and small & large customers are delivered jointly
    • Small & Large Customers
      • Combined shipment cost for 2 customers:
S* = S + s1 +...+ s14
S* = $ 350 + (14 x $ 50 ) = $ 1.050
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(14 x 156.000 x 0,25 x $1) / 2 x $1.050
2 S*
= √546.000 / 2.100
= 16,1 ≈ 17 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 17 x ($1.050/14) = $1.275
      • Quantity Shipped for Each Customers:
Q = 156.000 / 17 = 9.175 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (9.175/2)
= $1.146,825
      • Total Capacity per truck:
Total capacity per truck = 14 x 9.175 = 128.450
Need added frequency
Shipment quantity for each truckload = 40.000/14 = 2.857
Increased in shipment frequency = 72.000/2.857 = 54,6 ≈ 55 x
Increased in annual shipment per customers = 55 x ($750/14) = $4.125
Decreased in annual holding cost
Q = 156.000/55 = 2.836
Annual holding cost = 0,25 x 1 x (2.836/2) = $354,5
Total Cost:
Medium = ($975x 6 ) + ($833,3 x 6) = $10.849,8
Small & Large = ($4.125 x 14 ) + ($354,5 x 14) = $ 62.713,0
Total $73.562,8
If Large customer are delivered independently and Medium & Small customers are delivered jointly
    • Medium & Small Customers
      • Combined shipment cost for 2 customers:
S* = S + s1 +...+ s18
S* = $ 350 + (18 x $ 50 ) = $ 1.250
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(18 x 72.000 x 0,25 x $1) / 2 x $1.250
2 S*
= √324.000 / 2.500
= 11,38 ≈ 12 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 12 x ($1.250/12) = $833,3
      • Quantity Shipped for Each Customers:
Q = 72.000 / 12 = 6.000 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (6.000/2)
= $750
      • Total Capacity per truck:
Total capacity per truck = 12 x 6.000 = 72.000
Need added frequency
Shipment quantity for each truckload = 40.000/12 = 3.333
Increased in shipment frequency = 72.000/3.333 = 21.6 ≈ 22 x
Increased in annual shipment per customers = 22 x ($1.250/18) = $1.527,8
Decreased in annual holding cost
Q = 72.000/22 = 3.273
Annual holding cost = 0,25 x 1 x (2.836/2) = $409,125
Total Cost:
Large = ($2.025 x 2 ) + ($4000 x 2) = $12.050,0
Small & Medium = ($1.527,8 x 18 ) + ($409,125 x 18) = $ 34.864,65
Total $46.914,65

If all type of customers are delivered jointly
      • Combined shipment cost for 20 customers:
S* = S + s1 +...+ s20
S* = $ 350 + (20 x $ 50 ) = $ 1.350
      • Optimal Shipment Frequency:
n* = √ki=1 Di h Ci = √(20 x 216.000 x 0,25 x $1) / 2 x $1.350
2 S*
= √1.080.000 / 2.700
= 20 x
      • Annual Shipment Cost per Customers:
Annual Shipment Cost = 20 x ($1.350/20) = $1.350
      • Quantity Shipped for Each Customers:
Q = 216.000 / 20 = 10.800 pounds
      • Annual Holding Cost per Customers:
Annual holding cost per costumers = h Ci Q/2
= 0,25 x $1 x (10.800/2)
= $1.350
      • Total Capacity per truck:
Total capacity per truck = 20 x 10.800 = 216.000 pounds
Need to add frequency
Shipment quantity for each truckload = 40.000/20 = 2.000
Increased in shipment frequency = 216.000/2000 = 108 x
Increased in annual shipment per customers = 108 x (1.350/20) = $7.290
Decreased in annual holding cost
Q = 216.000/108 = 2000
Annual holding cost = 0,25 x 1 x (2000/2) = $250
Total Cost = ($7.290 x 20) + ($250 x 20) = $150.800







Summary

Scenario
Total Cost
If each type of customers are delivered independently

$31.249,4

If small customer are delivered independently and medium & large customers are delivered jointly

$44.075,6

If medium customer are delivered independently and small & large customers are delivered jointly

$73.562,8
If Large customer are delivered independently and Medium & Small customers are delivered jointly

$46.914,65
If all type of customers are delivered jointly

$150.800

Conclusion:
From the calculation above we got the lowest annual cost is $24.399,6. Delivery option that we recommend to use for MoonChem is independent delivery for small customers and joint delivery for medium & large customers.

  1. Impact


2 komentar:

  1. assalamualaikum wr. wb.
    mas annas, jazakumullah khoiron katsir atas posting mas dalam kasus moonchem ini...
    sungguh, sangat membantu kami dalam menyelasaikan kasus dalam mata kuliah Supply Chain Management yang kami tempuh....
    Semoga ALLAH Swt. memberikan pahala yang setimpal atas amal baik yang mas anas lakukan
    amien3x....

    BalasHapus
  2. assalamualaikum wr.wb..

    aih terima kasih sekali mas, postingan mas sungguh sangat membantu saya dan kawan-kawan dalam belajar.
    semoga Allah SWT membalas amal bakti mas..SMANGAT MAS!!!^-^

    BalasHapus

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